16 Jan
2012
16 Jan
'12
4:23 p.m.
On 16 January 2012 11:22, Calvin Morrison <mutantturkey(a)gmail.com> wrote:
On 16 January 2012 09:59, Darrell Anderson <humanreadable(a)yahoo.com>wrote;wrote:
Ok. Thanks. I haven't gotten that far in my studies of C++ and none of
the simplistic examples on the web provided an answer. :)
Darrell
Consider this function however
int main() {
// define two integers
int x = 3;
int y = 4;
//print out a message telling which is bigger
if (x > y) {
}
else {
cout << "x is smaller than y" << endl;
}
return 0;
}
Sorry! gmail keeps sending my emails half way done!
int main() {
// define two integers
int x = 3;
int y = 4;
//print out a message telling which is bigger
if (x > y) {
return 1;
}
else {
cout << "x is smaller than y" << endl;
}
return 0;
}
In this example, if X > Y then it would return. of course if X was not
greater than Y it would return a the end of the function normally.
When a C++ (boolean) function contains multiple
if-else tests, and each of those tests contains a return
statement (return=false; or return=true;), does the function
exit when encountering the first return?
Or does the function continue executing the remaining
code within that function?
In other words, when encountering that first return,
does the function exit much
like a break command?
Code always returns from the function when the first return
is executed.