16 Jan
2012
16 Jan
'12
6:24 p.m.
Le lundi 16 janvier 2012, Darrell Anderson a écrit :
When a C++ (boolean) function contains multiple
if-else tests, and each of
those tests contains a return statement (return=false; or return=true;),
does the function exit when encountering the first return?
Or does the function continue executing the remaining code within that
function?
In other words, when encountering that first return, does the function
exit much like a break command?
Darrell
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Hi everybody,
If it returns on this instruction "return=false;", does this writing
supose that the "=" operator had been overloaded? Can someone tel me the
interest of overloading the "=" operator for a return instruction? It just
looks to me like adding ambigiusity, even if the reader knows that "return"
is a reserved word and not an variable identifier. The old
K&R "return(expression);" looks definitively clearer to me.
I personely would write something like
if (IsRouge()) return(Red());
if (IsJaune()) return(Yellow());
... rather than
if (IsRouge) return(Red());
else if (IsJaune return(Yellow());
Is'nt that "else" keyword adding ambigiusity, reason why this thread
exists? Furthermore: depending of the compiler and optimisation, I suppose
that code could be added because the "else" keyword existance.
Thank you,
Patrick